Base | Representation |
---|---|
bin | 1100011010101111000… |
… | …0011111011010101011 |
3 | 202101122200110112110002 |
4 | 3012223300133122223 |
5 | 11443402230404120 |
6 | 242001005413215 |
7 | 21261432456014 |
oct | 3065360373253 |
9 | 671580415402 |
10 | 213335013035 |
11 | 82525064931 |
12 | 3541956a20b |
13 | 1716ac2a631 |
14 | a47b13600b |
15 | 5838eee375 |
hex | 31abc1f6ab |
213335013035 has 8 divisors (see below), whose sum is σ = 256004642880. Its totient is φ = 170666258944.
The previous prime is 213335013029. The next prime is 213335013079. The reversal of 213335013035 is 530310533312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 213335013035 - 222 = 213330818731 is a prime.
It is a super-2 number, since 2×2133350130352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 213335012989 and 213335013007.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 586094 + ... + 877596.
It is an arithmetic number, because the mean of its divisors is an integer number (32000580360).
Almost surely, 2213335013035 is an apocalyptic number.
213335013035 is a deficient number, since it is larger than the sum of its proper divisors (42669629845).
213335013035 is a wasteful number, since it uses less digits than its factorization.
213335013035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437877.
The product of its (nonzero) digits is 12150, while the sum is 29.
Adding to 213335013035 its reverse (530310533312), we get a palindrome (743645546347).
The spelling of 213335013035 in words is "two hundred thirteen billion, three hundred thirty-five million, thirteen thousand, thirty-five".
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