Base | Representation |
---|---|
bin | 11111000011011100011… |
… | …000101010000011011001 |
3 | 21120000020012210122100010 |
4 | 133003130120222003121 |
5 | 234430413303330131 |
6 | 4312202512232133 |
7 | 310114353111102 |
oct | 37033430520331 |
9 | 7500205718303 |
10 | 2134001230041 |
11 | 7530300742aa |
12 | 2a570083b649 |
13 | 12630a39b435 |
14 | 7540150d3a9 |
15 | 3a79c25ab46 |
hex | 1f0dc62a0d9 |
2134001230041 has 8 divisors (see below), whose sum is σ = 2845342104640. Its totient is φ = 1422663921072.
The previous prime is 2134001230037. The next prime is 2134001230093. The reversal of 2134001230041 is 1400321004312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2134001230041 - 22 = 2134001230037 is a prime.
It is a super-2 number, since 2×21340012300412 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2134001230021) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1218531 + ... + 2398503.
It is an arithmetic number, because the mean of its divisors is an integer number (355667763080).
Almost surely, 22134001230041 is an apocalyptic number.
It is an amenable number.
2134001230041 is a deficient number, since it is larger than the sum of its proper divisors (711340874599).
2134001230041 is a wasteful number, since it uses less digits than its factorization.
2134001230041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1782815.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 2134001230041 its reverse (1400321004312), we get a palindrome (3534322234353).
It can be divided in two parts, 213400 and 1230041, that added together give a palindrome (1443441).
The spelling of 2134001230041 in words is "two trillion, one hundred thirty-four billion, one million, two hundred thirty thousand, forty-one".
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