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21341031412403 = 55217386493859
BaseRepresentation
bin1001101101000110110001…
…00110001011001010110011
32210120011221011122200012202
410312203120212023022303
510244122413020144103
6113215533503213415
74331560436655323
oct466433046131263
983504834580182
1021341031412403
11688875396670a
1224880502a726b
13bba5b2048711
1453aca8d7b283
152701e10cb988
hex1368d898b2b3

21341031412403 has 4 divisors (see below), whose sum is σ = 21341417961480. Its totient is φ = 21340644863328.

The previous prime is 21341031412399. The next prime is 21341031412423. The reversal of 21341031412403 is 30421413014312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21341031412403 - 22 = 21341031412399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21341031412423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193191713 + ... + 193302146.

It is an arithmetic number, because the mean of its divisors is an integer number (5335354490370).

Almost surely, 221341031412403 is an apocalyptic number.

21341031412403 is a deficient number, since it is larger than the sum of its proper divisors (386549077).

21341031412403 is an equidigital number, since it uses as much as digits as its factorization.

21341031412403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 386549076.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 21341031412403 its reverse (30421413014312), we get a palindrome (51762444426715).

The spelling of 21341031412403 in words is "twenty-one trillion, three hundred forty-one billion, thirty-one million, four hundred twelve thousand, four hundred three".

Divisors: 1 55217 386493859 21341031412403