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2134113403 = 15713593079
BaseRepresentation
bin111111100110011…
…1111110001111011
312111201201012020011
41333030333301323
513332313112103
6551433242351
7103612443652
oct17714776173
95451635204
102134113403
119a5718a94
124b68633b7
132801a31c6
1416360a199
15c7554d6d
hex7f33fc7b

2134113403 has 4 divisors (see below), whose sum is σ = 2147706640. Its totient is φ = 2120520168.

The previous prime is 2134113361. The next prime is 2134113407. The reversal of 2134113403 is 3043114312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2134113403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2134113407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6796383 + ... + 6796696.

It is an arithmetic number, because the mean of its divisors is an integer number (536926660).

Almost surely, 22134113403 is an apocalyptic number.

2134113403 is a deficient number, since it is larger than the sum of its proper divisors (13593237).

2134113403 is a wasteful number, since it uses less digits than its factorization.

2134113403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13593236.

The product of its (nonzero) digits is 864, while the sum is 22.

The square root of 2134113403 is about 46196.4652652127. The cubic root of 2134113403 is about 1287.4760663914.

Adding to 2134113403 its reverse (3043114312), we get a palindrome (5177227715).

Subtracting 2134113403 from its reverse (3043114312), we obtain a palindrome (909000909).

The spelling of 2134113403 in words is "two billion, one hundred thirty-four million, one hundred thirteen thousand, four hundred three".

Divisors: 1 157 13593079 2134113403