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2134131121 = 2638114567
BaseRepresentation
bin111111100110100…
…0100000110110001
312111201202002112101
41333031010012301
513332314143441
6551433500401
7103612546423
oct17715040661
95451662471
102134131121
119a5730331
124b6871701
132801ab2a5
14163612813
15c755a231
hex7f3441b1

2134131121 has 4 divisors (see below), whose sum is σ = 2142245952. Its totient is φ = 2126016292.

The previous prime is 2134131119. The next prime is 2134131133. The reversal of 2134131121 is 1211314312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2134131121 - 21 = 2134131119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2134131821) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4057021 + ... + 4057546.

It is an arithmetic number, because the mean of its divisors is an integer number (535561488).

Almost surely, 22134131121 is an apocalyptic number.

It is an amenable number.

2134131121 is a deficient number, since it is larger than the sum of its proper divisors (8114831).

2134131121 is an equidigital number, since it uses as much as digits as its factorization.

2134131121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8114830.

The product of its digits is 144, while the sum is 19.

The square root of 2134131121 is about 46196.6570327334. The cubic root of 2134131121 is about 1287.4796293758.

Adding to 2134131121 its reverse (1211314312), we get a palindrome (3345445433).

The spelling of 2134131121 in words is "two billion, one hundred thirty-four million, one hundred thirty-one thousand, one hundred twenty-one".

Divisors: 1 263 8114567 2134131121