Base | Representation |
---|---|
bin | 1100011011000001111… |
… | …0101001000100001011 |
3 | 202101212012111200000222 |
4 | 3012300132221010023 |
5 | 11444033020020133 |
6 | 242012515220255 |
7 | 21263413640153 |
oct | 3066036510413 |
9 | 671765450028 |
10 | 213414220043 |
11 | 82565844272 |
12 | 3543bba768b |
13 | 17181470a9b |
14 | a487873763 |
15 | 5840e47e98 |
hex | 31b07a910b |
213414220043 has 4 divisors (see below), whose sum is σ = 213478640568. Its totient is φ = 213349799520.
The previous prime is 213414220009. The next prime is 213414220051. The reversal of 213414220043 is 340022414312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 213414220043 - 212 = 213414215947 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 213414219994 and 213414220021.
It is not an unprimeable number, because it can be changed into a prime (213414220093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32205293 + ... + 32211918.
It is an arithmetic number, because the mean of its divisors is an integer number (53369660142).
Almost surely, 2213414220043 is an apocalyptic number.
213414220043 is a deficient number, since it is larger than the sum of its proper divisors (64420525).
213414220043 is an equidigital number, since it uses as much as digits as its factorization.
213414220043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 64420524.
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 213414220043 its reverse (340022414312), we get a palindrome (553436634355).
The spelling of 213414220043 in words is "two hundred thirteen billion, four hundred fourteen million, two hundred twenty thousand, forty-three".
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