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213443101145 = 5125833392563
BaseRepresentation
bin1100011011001000110…
…0110100000111011001
3202101221012211222110102
43012302030310013121
511444112413214040
6242015430225145
721264214265501
oct3066214640731
9671835758412
10213443101145
118258008004a
12354497b51b5
13171874436b1
14a48b630a01
155843750515
hex31b23341d9

213443101145 has 8 divisors (see below), whose sum is σ = 256152152256. Its totient is φ = 170740860336.

The previous prime is 213443101087. The next prime is 213443101147. The reversal of 213443101145 is 541101344312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213443101145 is a prime.

It is a super-2 number, since 2×2134431011452 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (213443101147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1633367 + ... + 1759196.

It is an arithmetic number, because the mean of its divisors is an integer number (32019019032).

Almost surely, 2213443101145 is an apocalyptic number.

It is an amenable number.

213443101145 is a deficient number, since it is larger than the sum of its proper divisors (42709051111).

213443101145 is a wasteful number, since it uses less digits than its factorization.

213443101145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3405151.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 213443101145 its reverse (541101344312), we get a palindrome (754544445457).

The spelling of 213443101145 in words is "two hundred thirteen billion, four hundred forty-three million, one hundred one thousand, one hundred forty-five".

Divisors: 1 5 12583 62915 3392563 16962815 42688620229 213443101145