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21345054313 = 111940459483
BaseRepresentation
bin10011111000010000…
…111010111001101001
32001002120111002220011
4103320100322321221
5322203313214223
613450014331521
71353643653022
oct237020727151
961076432804
1021345054313
1190637aa260
1241784b9ba1
132022258b6b
141066bb3c49
1584ddaa80d
hex4f843ae69

21345054313 has 4 divisors (see below), whose sum is σ = 23285513808. Its totient is φ = 19404594820.

The previous prime is 21345054299. The next prime is 21345054317. The reversal of 21345054313 is 31345054312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21345054313 - 221 = 21342957161 is a prime.

It is a super-2 number, since 2×213450543132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21345054317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 970229731 + ... + 970229752.

It is an arithmetic number, because the mean of its divisors is an integer number (5821378452).

Almost surely, 221345054313 is an apocalyptic number.

It is an amenable number.

21345054313 is a deficient number, since it is larger than the sum of its proper divisors (1940459495).

21345054313 is a wasteful number, since it uses less digits than its factorization.

21345054313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1940459494.

The product of its (nonzero) digits is 21600, while the sum is 31.

Subtracting 21345054313 from its reverse (31345054312), we obtain a palindrome (9999999999).

The spelling of 21345054313 in words is "twenty-one billion, three hundred forty-five million, fifty-four thousand, three hundred thirteen".

Divisors: 1 11 1940459483 21345054313