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2135252520121 = 7305036074303
BaseRepresentation
bin11111000100100110111…
…101111100110010111001
321120010110102022202122011
4133010212331330302321
5234440444121120441
64312531011525521
7310160355646120
oct37044675746271
97503412282564
102135252520121
11753612422036
122a59ab8b98a1
131264796b0276
14754bd790ab7
153a822028581
hex1f126f7ccb9

2135252520121 has 4 divisors (see below), whose sum is σ = 2440288594432. Its totient is φ = 1830216445812.

The previous prime is 2135252520097. The next prime is 2135252520131. The reversal of 2135252520121 is 1210252525312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2135252520121 - 215 = 2135252487353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2135252520131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152518037145 + ... + 152518037158.

It is an arithmetic number, because the mean of its divisors is an integer number (610072148608).

Almost surely, 22135252520121 is an apocalyptic number.

It is an amenable number.

2135252520121 is a deficient number, since it is larger than the sum of its proper divisors (305036074311).

2135252520121 is an equidigital number, since it uses as much as digits as its factorization.

2135252520121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 305036074310.

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 2135252520121 in words is "two trillion, one hundred thirty-five billion, two hundred fifty-two million, five hundred twenty thousand, one hundred twenty-one".

Divisors: 1 7 305036074303 2135252520121