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21361550057 = 181431177399
BaseRepresentation
bin10011111001001111…
…110110001011101001
32001010201112011210122
4103321033312023221
5322222024100212
613451404053025
71354234115411
oct237117661351
961121464718
1021361550057
119072046801
124181b34175
1320257b3263
141069069641
15850568272
hex4f93f62e9

21361550057 has 4 divisors (see below), whose sum is σ = 21362745600. Its totient is φ = 21360354516.

The previous prime is 21361550053. The next prime is 21361550117. The reversal of 21361550057 is 75005516312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21361550057 - 22 = 21361550053 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21361549999 and 21361550026.

It is not an unprimeable number, because it can be changed into a prime (21361550053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 570557 + ... + 606842.

It is an arithmetic number, because the mean of its divisors is an integer number (5340686400).

Almost surely, 221361550057 is an apocalyptic number.

It is an amenable number.

21361550057 is a deficient number, since it is larger than the sum of its proper divisors (1195543).

21361550057 is a wasteful number, since it uses less digits than its factorization.

21361550057 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1195542.

The product of its (nonzero) digits is 31500, while the sum is 35.

The spelling of 21361550057 in words is "twenty-one billion, three hundred sixty-one million, five hundred fifty thousand, fifty-seven".

Divisors: 1 18143 1177399 21361550057