Base | Representation |
---|---|
bin | 1001101101110100011101… |
… | …01000010110100011111011 |
3 | 2210122112020122000220110121 |
4 | 10312322032220112203323 |
5 | 10300023131412220042 |
6 | 113235111453554111 |
7 | 4333416333565006 |
oct | 466721650264373 |
9 | 83575218026417 |
10 | 21365560273147 |
11 | 68980a0858852 |
12 | 2490956aa5937 |
13 | bbc9c0a933bc |
14 | 53c15492253d |
15 | 270b79737367 |
hex | 136e8ea168fb |
21365560273147 has 8 divisors (see below), whose sum is σ = 21537693544752. Its totient is φ = 21194116915200.
The previous prime is 21365560273129. The next prime is 21365560273153. The reversal of 21365560273147 is 74137206556312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 21365560273147 - 27 = 21365560273019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21365560273094 and 21365560273103.
It is not an unprimeable number, because it can be changed into a prime (21365560273247) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 172416229 + ... + 172540102.
It is an arithmetic number, because the mean of its divisors is an integer number (2692211693094).
Almost surely, 221365560273147 is an apocalyptic number.
21365560273147 is a deficient number, since it is larger than the sum of its proper divisors (172133271605).
21365560273147 is a wasteful number, since it uses less digits than its factorization.
21365560273147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 344956829.
The product of its (nonzero) digits is 6350400, while the sum is 52.
The spelling of 21365560273147 in words is "twenty-one trillion, three hundred sixty-five billion, five hundred sixty million, two hundred seventy-three thousand, one hundred forty-seven".
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