Base | Representation |
---|---|
bin | 11111001001000100100… |
… | …101001100001101000011 |
3 | 21120120211100221002021201 |
4 | 133021010211030031003 |
5 | 240030302321012121 |
6 | 4315042304402031 |
7 | 310420202346004 |
oct | 37110445141503 |
9 | 7516740832251 |
10 | 2140044313411 |
11 | 755651251284 |
12 | 2a6908616317 |
13 | 126a61370304 |
14 | 75815d351ab |
15 | 3aa02a53e91 |
hex | 1f24494c343 |
2140044313411 has 4 divisors (see below), whose sum is σ = 2140273425024. Its totient is φ = 2139815201800.
The previous prime is 2140044313333. The next prime is 2140044313417. The reversal of 2140044313411 is 1143134400412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2140044313411 - 225 = 2140010758979 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2140044313411.
It is not an unprimeable number, because it can be changed into a prime (2140044313417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114541795 + ... + 114560476.
It is an arithmetic number, because the mean of its divisors is an integer number (535068356256).
Almost surely, 22140044313411 is an apocalyptic number.
2140044313411 is a deficient number, since it is larger than the sum of its proper divisors (229111613).
2140044313411 is an equidigital number, since it uses as much as digits as its factorization.
2140044313411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 229111612.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 2140044313411 its reverse (1143134400412), we get a palindrome (3283178713823).
The spelling of 2140044313411 in words is "two trillion, one hundred forty billion, forty-four million, three hundred thirteen thousand, four hundred eleven".
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