2140113331 has 4 divisors (see below), whose sum is σ = 2140227000. Its totient is φ = 2139999664.

The previous prime is 2140113307. The next prime is 2140113347. The reversal of 2140113331 is 1333110412.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2140113331 - 2⁵ = 2140113299 is a prime.

It is a super-3 number, since 3×2140113331³ (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2140113299 and 2140113308.

It is not an unprimeable number, because it can be changed into a prime (2140113301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21106 + ... + 68743.

It is an arithmetic number, because the mean of its divisors is an integer number (535056750).

Almost surely, 2^2140113331 is an apocalyptic number.

2140113331 is a deficient number, since it is larger than the sum of its proper divisors (113669).

2140113331 is an equidigital number, since it uses as much as digits as its factorization.

2140113331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113668.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 2140113331 is about 46261.3589402646. The cubic root of 2140113331 is about 1288.6814905804.

Adding to 2140113331 its reverse (1333110412), we get a palindrome (3473223743).

The spelling of 2140113331 in words is "two billion, one hundred forty million, one hundred thirteen thousand, three hundred thirty-one".