2140113544001 has 4 divisors (see below), whose sum is σ = 2140480070400. Its totient is φ = 2139747017604.

The previous prime is 2140113543913. The next prime is 2140113544003. The reversal of 2140113544001 is 1004453110412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2140113544001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2140113544003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183254441 + ... + 183266118.

It is an arithmetic number, because the mean of its divisors is an integer number (535120017600).

Almost surely, 2^{2140113544001} is an apocalyptic number.

It is an amenable number.

2140113544001 is a deficient number, since it is larger than the sum of its proper divisors (366526399).

2140113544001 is an equidigital number, since it uses as much as digits as its factorization.

2140113544001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 366526398.

The product of its (nonzero) digits is 1920, while the sum is 26.

Adding to 2140113544001 its reverse (1004453110412), we get a palindrome (3144566654413).

The spelling of 2140113544001 in words is "two trillion, one hundred forty billion, one hundred thirteen million, five hundred forty-four thousand, one".