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2140115 = 5428023
BaseRepresentation
bin1000001010011111010011
311000201200112
420022133103
51021440430
6113511535
724122255
oct10123723
94021615
102140115
11123199a
128725ab
1359c153
143d9cd5
152c4195
hex20a7d3

2140115 has 4 divisors (see below), whose sum is σ = 2568144. Its totient is φ = 1712088.

The previous prime is 2140109. The next prime is 2140121. The reversal of 2140115 is 5110412.

2140115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (2140109) and next prime (2140121).

It is a cyclic number.

It is not a de Polignac number, because 2140115 - 28 = 2139859 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2140115.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214007 + ... + 214016.

It is an arithmetic number, because the mean of its divisors is an integer number (642036).

22140115 is an apocalyptic number.

2140115 is a deficient number, since it is larger than the sum of its proper divisors (428029).

2140115 is an equidigital number, since it uses as much as digits as its factorization.

2140115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 428028.

The product of its (nonzero) digits is 40, while the sum is 14.

The square root of 2140115 is about 1462.9131894955. The cubic root of 2140115 is about 128.8681825580.

Adding to 2140115 its reverse (5110412), we get a palindrome (7250527).

The spelling of 2140115 in words is "two million, one hundred forty thousand, one hundred fifteen".

Divisors: 1 5 428023 2140115