214013211 has 4 divisors (see below), whose sum is σ = 285350952. Its totient is φ = 142675472.

The previous prime is 214013201. The next prime is 214013251. The reversal of 214013211 is 112310412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 214013211 - 2⁵ = 214013179 is a prime.

It is not an unprimeable number, because it can be changed into a prime (214013201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35668866 + ... + 35668871.

It is an arithmetic number, because the mean of its divisors is an integer number (71337738).

Almost surely, 2^214013211 is an apocalyptic number.

214013211 is a deficient number, since it is larger than the sum of its proper divisors (71337741).

214013211 is an equidigital number, since it uses as much as digits as its factorization.

214013211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71337740.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 214013211 is about 14629.1903740433. The cubic root of 214013211 is about 598.1547112224.

Adding to 214013211 its reverse (112310412), we get a palindrome (326323623).

It can be divided in two parts, 2140 and 13211, that added together give a palindrome (15351).

The spelling of 214013211 in words is "two hundred fourteen million, thirteen thousand, two hundred eleven".