Base | Representation |
---|---|
bin | 110000101010010100000110… |
… | …010011010110110110010011 |
3 | 1001001202112121210121021020112 |
4 | 300222110012103112312103 |
5 | 211022401213432130003 |
6 | 2035100404424231535 |
7 | 63036001125426626 |
oct | 6052240623266623 |
9 | 1031675553537215 |
10 | 214014031130003 |
11 | 62211928269645 |
12 | 2000542a00b5ab |
13 | 925558a101100 |
14 | 3abc49774ddbd |
15 | 19b1ee1bbe3d8 |
hex | c2a5064d6d93 |
214014031130003 has 6 divisors (see below), whose sum is σ = 231743004123204. Its totient is φ = 197551413350616.
The previous prime is 214014031129931. The next prime is 214014031130047. The reversal of 214014031130003 is 300031130410412.
It is not a de Polignac number, because 214014031130003 - 218 = 214014030867859 is a prime.
It is a super-2 number, since 2×2140140311300032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (214014036130003) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 633177606725 + ... + 633177607062.
It is an arithmetic number, because the mean of its divisors is an integer number (38623834020534).
Almost surely, 2214014031130003 is an apocalyptic number.
214014031130003 is a deficient number, since it is larger than the sum of its proper divisors (17728972993201).
214014031130003 is a wasteful number, since it uses less digits than its factorization.
214014031130003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1266355213813 (or 1266355213800 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 214014031130003 its reverse (300031130410412), we get a palindrome (514045161540415).
The spelling of 214014031130003 in words is "two hundred fourteen trillion, fourteen billion, thirty-one million, one hundred thirty thousand, three".
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