2140153121 has 4 divisors (see below), whose sum is σ = 2140320000. Its totient is φ = 2139986244.

The previous prime is 2140153087. The next prime is 2140153139. The reversal of 2140153121 is 1213510412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2140153121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2140153093 and 2140153102.

It is not an unprimeable number, because it can be changed into a prime (2140153321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62441 + ... + 90438.

It is an arithmetic number, because the mean of its divisors is an integer number (535080000).

Almost surely, 2^2140153121 is an apocalyptic number.

It is an amenable number.

2140153121 is a deficient number, since it is larger than the sum of its proper divisors (166879).

2140153121 is a wasteful number, since it uses less digits than its factorization.

2140153121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 166878.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 2140153121 is about 46261.7889948065. The cubic root of 2140153121 is about 1288.6894771230.

Adding to 2140153121 its reverse (1213510412), we get a palindrome (3353663533).

The spelling of 2140153121 in words is "two billion, one hundred forty million, one hundred fifty-three thousand, one hundred twenty-one".