214021113 has 4 divisors (see below), whose sum is σ = 285361488. Its totient is φ = 142680740.

The previous prime is 214021103. The next prime is 214021139. The reversal of 214021113 is 311120412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 214021113 - 2¹⁴ = 214004729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 214021092 and 214021101.

It is not an unprimeable number, because it can be changed into a prime (214021103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35670183 + ... + 35670188.

It is an arithmetic number, because the mean of its divisors is an integer number (71340372).

Almost surely, 2^214021113 is an apocalyptic number.

It is an amenable number.

214021113 is a deficient number, since it is larger than the sum of its proper divisors (71340375).

214021113 is an equidigital number, since it uses as much as digits as its factorization.

214021113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71340374.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 214021113 is about 14629.4604480138. The cubic root of 214021113 is about 598.1620730114.

Adding to 214021113 its reverse (311120412), we get a palindrome (525141525).

The spelling of 214021113 in words is "two hundred fourteen million, twenty-one thousand, one hundred thirteen".