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21403113 = 331373617
BaseRepresentation
bin101000110100…
…1010111101001
31111021101112220
41101221113221
520434344423
62042424253
7346631514
oct121512751
944241486
1021403113
1111099526
127202089
134584c84
142bb1d7b
151d2b9e3
hex14695e9

21403113 has 16 divisors (see below), whose sum is σ = 29584896. Its totient is φ = 13749120.

The previous prime is 21403111. The next prime is 21403117. The reversal of 21403113 is 31130412.

It is not a de Polignac number, because 21403113 - 21 = 21403111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21403092 and 21403101.

It is not an unprimeable number, because it can be changed into a prime (21403111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34381 + ... + 34997.

It is an arithmetic number, because the mean of its divisors is an integer number (1849056).

Almost surely, 221403113 is an apocalyptic number.

It is an amenable number.

21403113 is a deficient number, since it is larger than the sum of its proper divisors (8181783).

21403113 is a wasteful number, since it uses less digits than its factorization.

21403113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1024.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 21403113 is about 4626.3498570687. The cubic root of 21403113 is about 277.6465713805.

Adding to 21403113 its reverse (31130412), we get a palindrome (52533525).

It can be divided in two parts, 2140 and 3113, that added together give a triangular number (5253 = T102).

The spelling of 21403113 in words is "twenty-one million, four hundred three thousand, one hundred thirteen".

Divisors: 1 3 31 93 373 617 1119 1851 11563 19127 34689 57381 230141 690423 7134371 21403113