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214031401241 = 730575914463
BaseRepresentation
bin1100011101010101000…
…1000000000100011001
3202110110012211201110212
43013111101000010121
512001314014314431
6242154043420505
721314616615230
oct3072521000431
9673405751425
10214031401241
1182852167679
1235592824735
131724c2a3a68
14a50580db17
15587a20b72b
hex31d5440119

214031401241 has 4 divisors (see below), whose sum is σ = 244607315712. Its totient is φ = 183455486772.

The previous prime is 214031401217. The next prime is 214031401249. The reversal of 214031401241 is 142104130412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 214031401241 - 214 = 214031384857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (214031401249) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15287957225 + ... + 15287957238.

It is an arithmetic number, because the mean of its divisors is an integer number (61151828928).

Almost surely, 2214031401241 is an apocalyptic number.

It is an amenable number.

214031401241 is a deficient number, since it is larger than the sum of its proper divisors (30575914471).

214031401241 is an equidigital number, since it uses as much as digits as its factorization.

214031401241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30575914470.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 214031401241 its reverse (142104130412), we get a palindrome (356135531653).

The spelling of 214031401241 in words is "two hundred fourteen billion, thirty-one million, four hundred one thousand, two hundred forty-one".

Divisors: 1 7 30575914463 214031401241