21403311444433 has 4 divisors (see below), whose sum is σ = 21403329210468. Its totient is φ = 21403293678400.

The previous prime is 21403311444421. The next prime is 21403311444481. The reversal of 21403311444433 is 33444411330412.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4972668082704 + 16430643361729 = 2229948^2 + 4053473^2 .

It is a cyclic number.

It is not a de Polignac number, because 21403311444433 - 2²¹ = 21403309347281 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21403311444392 and 21403311444401.

It is not an unprimeable number, because it can be changed into a prime (21403311744433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6933268 + ... + 9532933.

It is an arithmetic number, because the mean of its divisors is an integer number (5350832302617).

Almost surely, 2^{21403311444433} is an apocalyptic number.

It is an amenable number.

21403311444433 is a deficient number, since it is larger than the sum of its proper divisors (17766035).

21403311444433 is a wasteful number, since it uses less digits than its factorization.

21403311444433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17766034.

The product of its (nonzero) digits is 165888, while the sum is 37.

Adding to 21403311444433 its reverse (33444411330412), we get a palindrome (54847722774845).

The spelling of 21403311444433 in words is "twenty-one trillion, four hundred three billion, three hundred eleven million, four hundred forty-four thousand, four hundred thirty-three".