21403312000001 has 4 divisors (see below), whose sum is σ = 21522883575600. Its totient is φ = 21283740424404.

The previous prime is 21403311999973. The next prime is 21403312000003. The reversal of 21403312000001 is 10000021330412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21403312000001 - 2¹⁴ = 21403311983617 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21403312000003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59785787531 + ... + 59785787888.

It is an arithmetic number, because the mean of its divisors is an integer number (5380720893900).

Almost surely, 2^{21403312000001} is an apocalyptic number.

It is an amenable number.

21403312000001 is a deficient number, since it is larger than the sum of its proper divisors (119571575599).

21403312000001 is a wasteful number, since it uses less digits than its factorization.

21403312000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119571575598.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 21403312000001 its reverse (10000021330412), we get a palindrome (31403333330413).

The spelling of 21403312000001 in words is "twenty-one trillion, four hundred three billion, three hundred twelve million, one", and thus it is an aban number.