214041112433 has 4 divisors (see below), whose sum is σ = 225306434160. Its totient is φ = 202775790708.

The previous prime is 214041112421. The next prime is 214041112451. The reversal of 214041112433 is 334211140412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 214041112433 - 2⁸ = 214041112177 is a prime.

It is a super-2 number, since 2×214041112433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (214041112133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5632660835 + ... + 5632660872.

It is an arithmetic number, because the mean of its divisors is an integer number (56326608540).

Almost surely, 2^214041112433 is an apocalyptic number.

It is an amenable number.

214041112433 is a deficient number, since it is larger than the sum of its proper divisors (11265321727).

214041112433 is a wasteful number, since it uses less digits than its factorization.

214041112433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11265321726.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 214041112433 its reverse (334211140412), we get a palindrome (548252252845).

The spelling of 214041112433 in words is "two hundred fourteen billion, forty-one million, one hundred twelve thousand, four hundred thirty-three".