Base | Representation |
---|---|
bin | 111111110010100… |
… | …0001100111110011 |
3 | 12112011120012211110 |
4 | 1333211001213303 |
5 | 13340421144103 |
6 | 552220244403 |
7 | 104020130253 |
oct | 17745014763 |
9 | 5464505743 |
10 | 2140412403 |
11 | 9a9230578 |
12 | 4b89a0703 |
13 | 28159a31c |
14 | 1643a9963 |
15 | c7d9b403 |
hex | 7f9419f3 |
2140412403 has 4 divisors (see below), whose sum is σ = 2853883208. Its totient is φ = 1426941600.
The previous prime is 2140412389. The next prime is 2140412411. The reversal of 2140412403 is 3042140412.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2140412403 - 29 = 2140411891 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2140412403.
It is not an unprimeable number, because it can be changed into a prime (2140412003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356735398 + ... + 356735403.
It is an arithmetic number, because the mean of its divisors is an integer number (713470802).
Almost surely, 22140412403 is an apocalyptic number.
2140412403 is a deficient number, since it is larger than the sum of its proper divisors (713470805).
2140412403 is an equidigital number, since it uses as much as digits as its factorization.
2140412403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 713470804.
The product of its (nonzero) digits is 768, while the sum is 21.
The square root of 2140412403 is about 46264.5912442767. The cubic root of 2140412403 is about 1288.7415170898.
Adding to 2140412403 its reverse (3042140412), we get a palindrome (5182552815).
The spelling of 2140412403 in words is "two billion, one hundred forty million, four hundred twelve thousand, four hundred three".
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