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214042433 = 1143452521
BaseRepresentation
bin11001100001000…
…00011101000001
3112220202111000112
430300200131001
5414243324213
633123401105
75206221263
oct1460403501
9486674015
10214042433
11aa904280
125b823195
1335462b37
14205d9b33
1513bceea8
hexcc20741

214042433 has 8 divisors (see below), whose sum is σ = 238931616. Its totient is φ = 190058400.

The previous prime is 214042403. The next prime is 214042441. The reversal of 214042433 is 334240412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 214042433 - 28 = 214042177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 214042399 and 214042408.

It is not an unprimeable number, because it can be changed into a prime (214042403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 225788 + ... + 226733.

It is an arithmetic number, because the mean of its divisors is an integer number (29866452).

Almost surely, 2214042433 is an apocalyptic number.

It is an amenable number.

214042433 is a deficient number, since it is larger than the sum of its proper divisors (24889183).

214042433 is a wasteful number, since it uses less digits than its factorization.

214042433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 452575.

The product of its (nonzero) digits is 2304, while the sum is 23.

The square root of 214042433 is about 14630.1890965223. The cubic root of 214042433 is about 598.1819345908.

Adding to 214042433 its reverse (334240412), we get a palindrome (548282845).

The spelling of 214042433 in words is "two hundred fourteen million, forty-two thousand, four hundred thirty-three".

Divisors: 1 11 43 473 452521 4977731 19458403 214042433