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2140431131 = 6151347981
BaseRepresentation
bin111111110010100…
…0110001100011011
312112011121011112002
41333211012030123
513340422244011
6552220511215
7104020235666
oct17745061433
95464534462
102140431131
119a9243653
124b89ab50b
132815a59c7
141643b26dd
15c7da1c3b
hex7f94631b

2140431131 has 4 divisors (see below), whose sum is σ = 2140785264. Its totient is φ = 2140077000.

The previous prime is 2140431127. The next prime is 2140431133. The reversal of 2140431131 is 1311340412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2140431131 - 22 = 2140431127 is a prime.

It is a super-2 number, since 2×21404311312 = 9162890853107878322, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2140431133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167840 + ... + 180141.

It is an arithmetic number, because the mean of its divisors is an integer number (535196316).

Almost surely, 22140431131 is an apocalyptic number.

2140431131 is a deficient number, since it is larger than the sum of its proper divisors (354133).

2140431131 is an equidigital number, since it uses as much as digits as its factorization.

2140431131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 354132.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 2140431131 is about 46264.7936448440. The cubic root of 2140431131 is about 1288.7452757862.

Adding to 2140431131 its reverse (1311340412), we get a palindrome (3451771543).

The spelling of 2140431131 in words is "two billion, one hundred forty million, four hundred thirty-one thousand, one hundred thirty-one".

Divisors: 1 6151 347981 2140431131