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214113258483 = 371371086161
BaseRepresentation
bin1100011101101000100…
…1010000101111110011
3202110122220212111111120
43013122021100233303
512002000443232413
6242210130113323
721316632445125
oct3073211205763
9673586774446
10214113258483
1182894397193
12355b611b843
13172632345b7
14a51263b215
1558824ca723
hex31da250bf3

214113258483 has 4 divisors (see below), whose sum is σ = 285484344648. Its totient is φ = 142742172320.

The previous prime is 214113258481. The next prime is 214113258493. The reversal of 214113258483 is 384852311412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 214113258483 - 21 = 214113258481 is a prime.

It is a super-2 number, since 2×2141132584832 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (214113258481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35685543078 + ... + 35685543083.

It is an arithmetic number, because the mean of its divisors is an integer number (71371086162).

Almost surely, 2214113258483 is an apocalyptic number.

214113258483 is a deficient number, since it is larger than the sum of its proper divisors (71371086165).

214113258483 is an equidigital number, since it uses as much as digits as its factorization.

214113258483 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71371086164.

The product of its digits is 184320, while the sum is 42.

Adding to 214113258483 its reverse (384852311412), we get a palindrome (598965569895).

The spelling of 214113258483 in words is "two hundred fourteen billion, one hundred thirteen million, two hundred fifty-eight thousand, four hundred eighty-three".

Divisors: 1 3 71371086161 214113258483