Base | Representation |
---|---|
bin | 1001101111001001101101… |
… | …10010010101001000110011 |
3 | 2210210220101110222112211100 |
4 | 10313210312302111020303 |
5 | 10301300401232242003 |
6 | 113312121342215443 |
7 | 4336626513515016 |
oct | 467446662251063 |
9 | 83726343875740 |
10 | 21411331134003 |
11 | 6905549261a88 |
12 | 24997ab584583 |
13 | bc41065c4215 |
14 | 5404576d337d |
15 | 271e57b93ba3 |
hex | 137936c95233 |
21411331134003 has 12 divisors (see below), whose sum is σ = 31227745085680. Its totient is φ = 14135636087856.
The previous prime is 21411331133999. The next prime is 21411331134023. The reversal of 21411331134003 is 30043113311412.
21411331134003 is a `hidden beast` number, since 2 + 1 + 4 + 1 + 1 + 3 + 311 + 340 + 0 + 3 = 666.
It is not a de Polignac number, because 21411331134003 - 22 = 21411331133999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21411331134023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11548721368 + ... + 11548723221.
Almost surely, 221411331134003 is an apocalyptic number.
21411331134003 is a deficient number, since it is larger than the sum of its proper divisors (9816413951677).
21411331134003 is a wasteful number, since it uses less digits than its factorization.
21411331134003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23097444698 (or 23097444695 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 21411331134003 its reverse (30043113311412), we get a palindrome (51454444445415).
The spelling of 21411331134003 in words is "twenty-one trillion, four hundred eleven billion, three hundred thirty-one million, one hundred thirty-four thousand, three".
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