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214120115 = 5113893093
BaseRepresentation
bin11001100001100…
…11011010110011
3112220220102120122
430300303122303
5414303320430
633125200455
75206663616
oct1460633263
9486812518
10214120115
11aa957680
125b86012b
133548c2c1
142061a17d
1513be7ee5
hexcc336b3

214120115 has 8 divisors (see below), whose sum is σ = 280302768. Its totient is φ = 155723680.

The previous prime is 214120111. The next prime is 214120189. The reversal of 214120115 is 511021412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 214120115 - 22 = 214120111 is a prime.

It is a super-2 number, since 2×2141201152 = 91694847295226450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 214120093 and 214120102.

It is not an unprimeable number, because it can be changed into a prime (214120111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1946492 + ... + 1946601.

It is an arithmetic number, because the mean of its divisors is an integer number (35037846).

Almost surely, 2214120115 is an apocalyptic number.

214120115 is a deficient number, since it is larger than the sum of its proper divisors (66182653).

214120115 is a wasteful number, since it uses less digits than its factorization.

214120115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3893109.

The product of its (nonzero) digits is 80, while the sum is 17.

The square root of 214120115 is about 14632.8437085893. The cubic root of 214120115 is about 598.2542915031.

Adding to 214120115 its reverse (511021412), we get a palindrome (725141527).

The spelling of 214120115 in words is "two hundred fourteen million, one hundred twenty thousand, one hundred fifteen".

Divisors: 1 5 11 55 3893093 19465465 42824023 214120115