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2141253613337 = 4349796595659
BaseRepresentation
bin11111001010001100101…
…010010011011100011001
321120200221122102212220212
4133022030222103130121
5240040241411111322
64315402304100505
7310462155256526
oct37121452233431
97520848385825
102141253613337
1175611192a203
122a6ba5604735
13126bc4a6c7b7
14758cc7a614d
153aa73cca0e2
hex1f28ca93719

2141253613337 has 4 divisors (see below), whose sum is σ = 2191050209040. Its totient is φ = 2091457017636.

The previous prime is 2141253613333. The next prime is 2141253613357. The reversal of 2141253613337 is 7333163521412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2141253613337 - 22 = 2141253613333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2141253613294 and 2141253613303.

It is not an unprimeable number, because it can be changed into a prime (2141253613333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24898297787 + ... + 24898297872.

It is an arithmetic number, because the mean of its divisors is an integer number (547762552260).

Almost surely, 22141253613337 is an apocalyptic number.

It is an amenable number.

2141253613337 is a deficient number, since it is larger than the sum of its proper divisors (49796595703).

2141253613337 is an equidigital number, since it uses as much as digits as its factorization.

2141253613337 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49796595702.

The product of its digits is 272160, while the sum is 41.

The spelling of 2141253613337 in words is "two trillion, one hundred forty-one billion, two hundred fifty-three million, six hundred thirteen thousand, three hundred thirty-seven".

Divisors: 1 43 49796595659 2141253613337