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2141312110403 = 6173470522059
BaseRepresentation
bin11111001010010000001…
…001011100111101000011
321120201002201111211210212
4133022100021130331003
5240040401400013103
64315412153544335
7310463465424104
oct37122011347503
97521081454725
102141312110403
11756141953994
122a70011150ab
13126c03c1164b
14758d64723ab
153aa78ed27d8
hex1f29025cf43

2141312110403 has 4 divisors (see below), whose sum is σ = 2144782633080. Its totient is φ = 2137841587728.

The previous prime is 2141312110321. The next prime is 2141312110447. The reversal of 2141312110403 is 3040112131412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2141312110403 - 234 = 2124132241219 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2141312610403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1735260413 + ... + 1735261646.

It is an arithmetic number, because the mean of its divisors is an integer number (536195658270).

Almost surely, 22141312110403 is an apocalyptic number.

2141312110403 is a deficient number, since it is larger than the sum of its proper divisors (3470522677).

2141312110403 is an equidigital number, since it uses as much as digits as its factorization.

2141312110403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3470522676.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 2141312110403 its reverse (3040112131412), we get a palindrome (5181424241815).

The spelling of 2141312110403 in words is "two trillion, one hundred forty-one billion, three hundred twelve million, one hundred ten thousand, four hundred three".

Divisors: 1 617 3470522059 2141312110403