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2142312113 = 18311170023
BaseRepresentation
bin111111110110001…
…0001011010110001
312112022010201202002
41333230101122301
513341412441423
6552325103345
7104042231624
oct17754213261
95468121662
102142312113
119aa308887
124b9557b55
13281ab3c06
14164741dbb
15c8124228
hex7fb116b1

2142312113 has 4 divisors (see below), whose sum is σ = 2143483968. Its totient is φ = 2141140260.

The previous prime is 2142312101. The next prime is 2142312121. The reversal of 2142312113 is 3112132412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2142312113 - 218 = 2142049969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2142317113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 583181 + ... + 586842.

It is an arithmetic number, because the mean of its divisors is an integer number (535870992).

Almost surely, 22142312113 is an apocalyptic number.

It is an amenable number.

2142312113 is a deficient number, since it is larger than the sum of its proper divisors (1171855).

2142312113 is a wasteful number, since it uses less digits than its factorization.

2142312113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1171854.

The product of its digits is 288, while the sum is 20.

The square root of 2142312113 is about 46285.1176189496. The cubic root of 2142312113 is about 1289.1226759100.

Adding to 2142312113 its reverse (3112132412), we get a palindrome (5254444525).

The spelling of 2142312113 in words is "two billion, one hundred forty-two million, three hundred twelve thousand, one hundred thirteen".

Divisors: 1 1831 1170023 2142312113