Base | Representation |
---|---|
bin | 11111001011111011100… |
… | …000111000100111110011 |
3 | 21120212202020222121101200 |
4 | 133023323200320213303 |
5 | 240103044013241110 |
6 | 4320311022102243 |
7 | 310556230314336 |
oct | 37137340704763 |
9 | 7525666877350 |
10 | 2143113415155 |
11 | 7569867198a9 |
12 | 2a742441a983 |
13 | 12713016a54b |
14 | 75a277a861d |
15 | 3ab321e76c0 |
hex | 1f2fb8389f3 |
2143113415155 has 12 divisors (see below), whose sum is σ = 3714729919680. Its totient is φ = 1142993821392.
The previous prime is 2143113415133. The next prime is 2143113415199. The reversal of 2143113415155 is 5515143113412.
2143113415155 is a `hidden beast` number, since 2 + 1 + 4 + 3 + 1 + 134 + 1 + 515 + 5 = 666.
It is not a de Polignac number, because 2143113415155 - 211 = 2143113413107 is a prime.
It is a super-2 number, since 2×21431134151552 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 23812371235 + ... + 23812371324.
It is an arithmetic number, because the mean of its divisors is an integer number (309560826640).
Almost surely, 22143113415155 is an apocalyptic number.
2143113415155 is a deficient number, since it is larger than the sum of its proper divisors (1571616504525).
2143113415155 is a wasteful number, since it uses less digits than its factorization.
2143113415155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47624742570 (or 47624742567 counting only the distinct ones).
The product of its digits is 36000, while the sum is 36.
Adding to 2143113415155 its reverse (5515143113412), we get a palindrome (7658256528567).
The spelling of 2143113415155 in words is "two trillion, one hundred forty-three billion, one hundred thirteen million, four hundred fifteen thousand, one hundred fifty-five".
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