Base | Representation |
---|---|
bin | 1100011110011100010… |
… | …1110000001010101011 |
3 | 202111020001112120211202 |
4 | 3013213011300022223 |
5 | 12002422043124121 |
6 | 242243445114415 |
7 | 21325210462331 |
oct | 3074705601253 |
9 | 674201476752 |
10 | 214330442411 |
11 | 82995a46738 |
12 | 356569b8a0b |
13 | 172992272b7 |
14 | a533413b51 |
15 | 58965cb40b |
hex | 31e71702ab |
214330442411 has 16 divisors (see below), whose sum is σ = 228170772000. Its totient is φ = 200627601408.
The previous prime is 214330442363. The next prime is 214330442423. The reversal of 214330442411 is 114244033412.
214330442411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-214330442411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (214330442111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23681015 + ... + 23690063.
It is an arithmetic number, because the mean of its divisors is an integer number (14260673250).
Almost surely, 2214330442411 is an apocalyptic number.
214330442411 is a deficient number, since it is larger than the sum of its proper divisors (13840329589).
214330442411 is a wasteful number, since it uses less digits than its factorization.
214330442411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16478.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 214330442411 its reverse (114244033412), we get a palindrome (328574475823).
The spelling of 214330442411 in words is "two hundred fourteen billion, three hundred thirty million, four hundred forty-two thousand, four hundred eleven".
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