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214331002011 = 3273402079397
BaseRepresentation
bin1100011110011100011…
…1111000110010011011
3202111020002121000110200
43013213013320302123
512002422214031021
6242243505113243
721325215312660
oct3074707706233
9674202530420
10214331002011
1182996299115
1235657028823
1317299391c19
14a53351ba67
15589668c126
hex31e71f8c9b

214331002011 has 12 divisors (see below), whose sum is σ = 353816257392. Its totient is φ = 122474858256.

The previous prime is 214331002009. The next prime is 214331002031. The reversal of 214331002011 is 110200133412.

214331002011 is a `hidden beast` number, since 21 + 433 + 10 + 0 + 201 + 1 = 666.

It is not a de Polignac number, because 214331002011 - 21 = 214331002009 is a prime.

It is not an unprimeable number, because it can be changed into a prime (214331002031) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1701039636 + ... + 1701039761.

It is an arithmetic number, because the mean of its divisors is an integer number (29484688116).

Almost surely, 2214331002011 is an apocalyptic number.

214331002011 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

214331002011 is a deficient number, since it is larger than the sum of its proper divisors (139485255381).

214331002011 is a wasteful number, since it uses less digits than its factorization.

214331002011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3402079410 (or 3402079407 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 214331002011 its reverse (110200133412), we get a palindrome (324531135423).

The spelling of 214331002011 in words is "two hundred fourteen billion, three hundred thirty-one million, two thousand, eleven".

Divisors: 1 3 7 9 21 63 3402079397 10206238191 23814555779 30618714573 71443667337 214331002011