Base | Representation |
---|---|
bin | 11111001100000111110… |
… | …110001111101110100011 |
3 | 21120220021200100112212002 |
4 | 133030013312033232203 |
5 | 240104010001411121 |
6 | 4320343333154215 |
7 | 310564322210024 |
oct | 37140766175643 |
9 | 7526250315762 |
10 | 2143320341411 |
11 | 756a82502637 |
12 | 2a748178b96b |
13 | 127163cab312 |
14 | 75a47070c4b |
15 | 3ab4546de0b |
hex | 1f307d8fba3 |
2143320341411 has 4 divisors (see below), whose sum is σ = 2143380244824. Its totient is φ = 2143260438000.
The previous prime is 2143320341389. The next prime is 2143320341417. The reversal of 2143320341411 is 1141430233412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2143320341411 - 230 = 2142246599587 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2143320341417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29898005 + ... + 29969606.
It is an arithmetic number, because the mean of its divisors is an integer number (535845061206).
Almost surely, 22143320341411 is an apocalyptic number.
2143320341411 is a deficient number, since it is larger than the sum of its proper divisors (59903413).
2143320341411 is an equidigital number, since it uses as much as digits as its factorization.
2143320341411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 59903412.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 2143320341411 its reverse (1141430233412), we get a palindrome (3284750574823).
The spelling of 2143320341411 in words is "two trillion, one hundred forty-three billion, three hundred twenty million, three hundred forty-one thousand, four hundred eleven".
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