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2143350550555 = 5428670110111
BaseRepresentation
bin11111001100001001101…
…001011111000000011011
321120220100210012100000021
4133030021221133000123
5240104040220104210
64320350332451311
7310565140036234
oct37141151370033
97526323170007
102143350550555
11756a98566175
122a748b919b37
1312716a327556
1475a4b09608b
153ab47e39bda
hex1f309a5f01b

2143350550555 has 4 divisors (see below), whose sum is σ = 2572020660672. Its totient is φ = 1714680440440.

The previous prime is 2143350550489. The next prime is 2143350550559. The reversal of 2143350550555 is 5550550533412.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2143350550555 - 227 = 2143216332827 is a prime.

It is a super-2 number, since 2×21433505505552 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2143350550559) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214335055051 + ... + 214335055060.

It is an arithmetic number, because the mean of its divisors is an integer number (643005165168).

Almost surely, 22143350550555 is an apocalyptic number.

2143350550555 is a deficient number, since it is larger than the sum of its proper divisors (428670110117).

2143350550555 is an equidigital number, since it uses as much as digits as its factorization.

2143350550555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 428670110116.

The product of its (nonzero) digits is 1125000, while the sum is 43.

The spelling of 2143350550555 in words is "two trillion, one hundred forty-three billion, three hundred fifty million, five hundred fifty thousand, five hundred fifty-five".

Divisors: 1 5 428670110111 2143350550555