Base | Representation |
---|---|
bin | 110000101111000011111111… |
… | …100010000011001000101011 |
3 | 1001002220201212111000011011220 |
4 | 300233003333202003020223 |
5 | 211043223001233233103 |
6 | 2035510331321553123 |
7 | 63101402213143404 |
oct | 6057037742031053 |
9 | 1032821774004156 |
10 | 214340335055403 |
11 | 62328253330367 |
12 | 200587146457a3 |
13 | 927a28c646acb |
14 | 3ad01b009c9ab |
15 | 19ba73d768c53 |
hex | c2f0ff88322b |
214340335055403 has 16 divisors (see below), whose sum is σ = 302930280539136. Its totient is φ = 134340426496640.
The previous prime is 214340335055393. The next prime is 214340335055419. The reversal of 214340335055403 is 304550533043412.
214340335055403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-214340335055403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (214340335056403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2306622951 + ... + 2306715872.
It is an arithmetic number, because the mean of its divisors is an integer number (18933142533696).
Almost surely, 2214340335055403 is an apocalyptic number.
214340335055403 is a deficient number, since it is larger than the sum of its proper divisors (88589945483733).
214340335055403 is a wasteful number, since it uses less digits than its factorization.
214340335055403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4613339754.
The product of its (nonzero) digits is 1296000, while the sum is 42.
Adding to 214340335055403 its reverse (304550533043412), we get a palindrome (518890868098815).
The spelling of 214340335055403 in words is "two hundred fourteen trillion, three hundred forty billion, three hundred thirty-five million, fifty-five thousand, four hundred three".
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