214424314433 has 18 divisors (see below), whose sum is σ = 258330121686. Its totient is φ = 177454570944.

The previous prime is 214424314411. The next prime is 214424314469. The reversal of 214424314433 is 334413424412.

214424314433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 3 ways, for example, as 62506000144 + 151918314289 = 250012^2 + 389767^2 .

It is not a de Polignac number, because 214424314433 - 2⁸ = 214424314177 is a prime.

It is a super-2 number, since 2×214424314433² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 214424314393 and 214424314402.

It is not an unprimeable number, because it can be changed into a prime (214424314033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 2560460 + ... + 2642877.

It is an arithmetic number, because the mean of its divisors is an integer number (14351673427).

Almost surely, 2^214424314433 is an apocalyptic number.

It is an amenable number.

214424314433 is a deficient number, since it is larger than the sum of its proper divisors (43905807253).

214424314433 is an equidigital number, since it uses as much as digits as its factorization.

214424314433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5203409 (or 5203373 counting only the distinct ones).

The product of its digits is 110592, while the sum is 35.

Adding to 214424314433 its reverse (334413424412), we get a palindrome (548837738845).

The spelling of 214424314433 in words is "two hundred fourteen billion, four hundred twenty-four million, three hundred fourteen thousand, four hundred thirty-three".