Base | Representation |
---|---|
bin | 11111001101000010110… |
… | …110101100000111100001 |
3 | 21120222211200011100011211 |
4 | 133031002312230013201 |
5 | 240113021420012231 |
6 | 4321025455510121 |
7 | 310631002633612 |
oct | 37150266540741 |
9 | 7528750140154 |
10 | 2144310313441 |
11 | 7574402a723a |
12 | 2a76b9228341 |
13 | 127291116c9a |
14 | 75adc72bc09 |
15 | 3aba231deb1 |
hex | 1f342dac1e1 |
2144310313441 has 4 divisors (see below), whose sum is σ = 2144404628884. Its totient is φ = 2144215998000.
The previous prime is 2144310313403. The next prime is 2144310313493. The reversal of 2144310313441 is 1443130134412.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 764437211041 + 1379873102400 = 874321^2 + 1174680^2 .
It is a cyclic number.
It is not a de Polignac number, because 2144310313441 - 227 = 2144176095713 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2144310313741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47123610 + ... + 47169091.
It is an arithmetic number, because the mean of its divisors is an integer number (536101157221).
Almost surely, 22144310313441 is an apocalyptic number.
It is an amenable number.
2144310313441 is a deficient number, since it is larger than the sum of its proper divisors (94315443).
2144310313441 is an equidigital number, since it uses as much as digits as its factorization.
2144310313441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 94315442.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 2144310313441 its reverse (1443130134412), we get a palindrome (3587440447853).
The spelling of 2144310313441 in words is "two trillion, one hundred forty-four billion, three hundred ten million, three hundred thirteen thousand, four hundred forty-one".
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