Base | Representation |
---|---|
bin | 11111001101000101001… |
… | …111101110100000001011 |
3 | 21120222221110122112110100 |
4 | 133031011033232200023 |
5 | 240113112202244433 |
6 | 4321033451420443 |
7 | 310632000632256 |
oct | 37150517564013 |
9 | 7528843575410 |
10 | 2144350431243 |
11 | 757460a08349 |
12 | 2a770a754723 |
13 | 127299522327 |
14 | 75b03bb209d |
15 | 3aba5ae5b13 |
hex | 1f3453ee80b |
2144350431243 has 12 divisors (see below), whose sum is σ = 3097490610760. Its totient is φ = 1429522857216.
The previous prime is 2144350431241. The next prime is 2144350431313. The reversal of 2144350431243 is 3421340534412.
2144350431243 is a `hidden beast` number, since 2 + 1 + 443 + 50 + 43 + 124 + 3 = 666.
It is not a de Polignac number, because 2144350431243 - 21 = 2144350431241 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2144350431198 and 2144350431207.
It is not an unprimeable number, because it can be changed into a prime (2144350431241) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3365398 + ... + 3951531.
Almost surely, 22144350431243 is an apocalyptic number.
2144350431243 is a deficient number, since it is larger than the sum of its proper divisors (953140179517).
2144350431243 is a wasteful number, since it uses less digits than its factorization.
2144350431243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7349498 (or 7349495 counting only the distinct ones).
The product of its (nonzero) digits is 138240, while the sum is 36.
Adding to 2144350431243 its reverse (3421340534412), we get a palindrome (5565690965655).
The spelling of 2144350431243 in words is "two trillion, one hundred forty-four billion, three hundred fifty million, four hundred thirty-one thousand, two hundred forty-three".
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