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2144482991417 = 13164960230109
BaseRepresentation
bin11111001101001101001…
…001011001110100111001
321121000021201002021211102
4133031031021121310321
5240113400121211132
64321054544541145
7310635200445134
oct37151511316471
97530251067742
102144482991417
11757519818808
122a77470217b5
131272bab261c0
1475b1763b21b
153abb257cc62
hex1f34d259d39

2144482991417 has 4 divisors (see below), whose sum is σ = 2309443221540. Its totient is φ = 1979522761296.

The previous prime is 2144482991393. The next prime is 2144482991437. The reversal of 2144482991417 is 7141992844412.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 212171705641 + 1932311285776 = 460621^2 + 1390076^2 .

It is a cyclic number.

It is not a de Polignac number, because 2144482991417 - 222 = 2144478797113 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2144482991437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82480115042 + ... + 82480115067.

It is an arithmetic number, because the mean of its divisors is an integer number (577360805385).

Almost surely, 22144482991417 is an apocalyptic number.

It is an amenable number.

2144482991417 is a deficient number, since it is larger than the sum of its proper divisors (164960230123).

2144482991417 is a wasteful number, since it uses less digits than its factorization.

2144482991417 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 164960230122.

The product of its digits is 4644864, while the sum is 56.

The spelling of 2144482991417 in words is "two trillion, one hundred forty-four billion, four hundred eighty-two million, nine hundred ninety-one thousand, four hundred seventeen".

Divisors: 1 13 164960230109 2144482991417