Search a number
-
+
214482015001 = 233391933997
BaseRepresentation
bin1100011111000000011…
…1111101001100011001
3202111121121202021100101
43013300013331030121
512003224343440001
6242310501535401
721332031022042
oct3076007751431
9674547667311
10214482015001
1182a63562441
1235699714561
13172c1756c17
14a5495cb8c9
1558a4a6ba01
hex31f01fd319

214482015001 has 4 divisors (see below), whose sum is σ = 214573951332. Its totient is φ = 214390078672.

The previous prime is 214482014953. The next prime is 214482015031. The reversal of 214482015001 is 100510284412.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 124397995401 + 90084019600 = 352701^2 + 300140^2 .

It is a cyclic number.

It is not a de Polignac number, because 214482015001 - 229 = 213945144089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (214482015031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45964666 + ... + 45969331.

It is an arithmetic number, because the mean of its divisors is an integer number (53643487833).

Almost surely, 2214482015001 is an apocalyptic number.

It is an amenable number.

214482015001 is a deficient number, since it is larger than the sum of its proper divisors (91936331).

214482015001 is an equidigital number, since it uses as much as digits as its factorization.

214482015001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91936330.

The product of its (nonzero) digits is 2560, while the sum is 28.

Adding to 214482015001 its reverse (100510284412), we get a palindrome (314992299413).

The spelling of 214482015001 in words is "two hundred fourteen billion, four hundred eighty-two million, fifteen thousand, one".

Divisors: 1 2333 91933997 214482015001