21450136040041 has 4 divisors (see below), whose sum is σ = 21452529236112. Its totient is φ = 21447742843972.

The previous prime is 21450136040009. The next prime is 21450136040057. The reversal of 21450136040041 is 14004063105412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21450136040041 - 2⁵ = 21450136040009 is a prime.

It is a super-2 number, since 2×21450136040041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21450136039985 and 21450136040012.

It is not an unprimeable number, because it can be changed into a prime (21450136340041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1196584591 + ... + 1196602516.

It is an arithmetic number, because the mean of its divisors is an integer number (5363132309028).

Almost surely, 2^{21450136040041} is an apocalyptic number.

It is an amenable number.

21450136040041 is a deficient number, since it is larger than the sum of its proper divisors (2393196071).

21450136040041 is an equidigital number, since it uses as much as digits as its factorization.

21450136040041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2393196070.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 21450136040041 its reverse (14004063105412), we get a palindrome (35454199145453).

The spelling of 21450136040041 in words is "twenty-one trillion, four hundred fifty billion, one hundred thirty-six million, forty thousand, forty-one".