Base | Representation |
---|---|
bin | 11111001101110011011… |
… | …011000011000110100011 |
3 | 21121001221110102101100211 |
4 | 133031303123003012203 |
5 | 240121204014314024 |
6 | 4321242404354551 |
7 | 310660125635665 |
oct | 37156333030643 |
9 | 7531843371324 |
10 | 2145125151139 |
11 | 757819251923 |
12 | 2a78a60a5a57 |
13 | 127390b93679 |
14 | 75b78a3a535 |
15 | 3abedb27594 |
hex | 1f3736c31a3 |
2145125151139 has 4 divisors (see below), whose sum is σ = 2174510427256. Its totient is φ = 2115739875024.
The previous prime is 2145125151133. The next prime is 2145125151149. The reversal of 2145125151139 is 9311515215412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2145125151139 - 25 = 2145125151107 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2145125151133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14692637949 + ... + 14692638094.
It is an arithmetic number, because the mean of its divisors is an integer number (543627606814).
Almost surely, 22145125151139 is an apocalyptic number.
2145125151139 is a deficient number, since it is larger than the sum of its proper divisors (29385276117).
2145125151139 is an equidigital number, since it uses as much as digits as its factorization.
2145125151139 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29385276116.
The product of its digits is 54000, while the sum is 40.
The spelling of 2145125151139 in words is "two trillion, one hundred forty-five billion, one hundred twenty-five million, one hundred fifty-one thousand, one hundred thirty-nine".
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