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21455113403 = 50349098689
BaseRepresentation
bin10011111110110100…
…110000110010111011
32001101020120200120202
4103332310300302323
5322420002112103
613504545312415
71356451312013
oct237664606273
961336520522
1021455113403
11910a941289
1241a933570b
13203bcb2099
141077662c43
1585889a988
hex4fed30cbb

21455113403 has 8 divisors (see below), whose sum is σ = 21504621600. Its totient is φ = 21405633408.

The previous prime is 21455113349. The next prime is 21455113429. The reversal of 21455113403 is 30431155412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21455113403 - 212 = 21455109307 is a prime.

It is a super-2 number, since 2×214551134032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21455112403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2464883 + ... + 2473571.

It is an arithmetic number, because the mean of its divisors is an integer number (2688077700).

Almost surely, 221455113403 is an apocalyptic number.

21455113403 is a deficient number, since it is larger than the sum of its proper divisors (49508197).

21455113403 is an equidigital number, since it uses as much as digits as its factorization.

21455113403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14101.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 21455113403 its reverse (30431155412), we get a palindrome (51886268815).

The spelling of 21455113403 in words is "twenty-one billion, four hundred fifty-five million, one hundred thirteen thousand, four hundred three".

Divisors: 1 503 4909 8689 2469227 4370567 42654301 21455113403