Base | Representation |
---|---|
bin | 11111001111110111011… |
… | …100111000001111110001 |
3 | 21121021122211110201100220 |
4 | 133033313130320033301 |
5 | 240140223044122343 |
6 | 4322250253203253 |
7 | 311066043511554 |
oct | 37176734701761 |
9 | 7537584421326 |
10 | 2147340223473 |
11 | 758755636515 |
12 | 2a8203a90529 |
13 | 127654a71563 |
14 | 75d08cbc69b |
15 | 3accd320183 |
hex | 1f3f77383f1 |
2147340223473 has 4 divisors (see below), whose sum is σ = 2863120297968. Its totient is φ = 1431560148980.
The previous prime is 2147340223463. The next prime is 2147340223517. The reversal of 2147340223473 is 3743220437412.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2147340223473 - 29 = 2147340222961 is a prime.
It is a super-2 number, since 2×21473402234732 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2147340223463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 357890037243 + ... + 357890037248.
It is an arithmetic number, because the mean of its divisors is an integer number (715780074492).
Almost surely, 22147340223473 is an apocalyptic number.
It is an amenable number.
2147340223473 is a deficient number, since it is larger than the sum of its proper divisors (715780074495).
2147340223473 is an equidigital number, since it uses as much as digits as its factorization.
2147340223473 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 715780074494.
The product of its (nonzero) digits is 677376, while the sum is 42.
The spelling of 2147340223473 in words is "two trillion, one hundred forty-seven billion, three hundred forty million, two hundred twenty-three thousand, four hundred seventy-three".
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