Base | Representation |
---|---|
bin | 11111001111111011001… |
… | …000000100010000000011 |
3 | 21121021211010111000101201 |
4 | 133033323020010100003 |
5 | 240140334340021413 |
6 | 4322300334442031 |
7 | 311100422532133 |
oct | 37177310042003 |
9 | 7537733430351 |
10 | 2147401876483 |
11 | 758787416316 |
12 | 2a8220663317 |
13 | 127664779a26 |
14 | 75d1316aac3 |
15 | 3acd394c9dd |
hex | 1f3fb204403 |
2147401876483 has 4 divisors (see below), whose sum is σ = 2160576121288. Its totient is φ = 2134227631680.
The previous prime is 2147401876481. The next prime is 2147401876493. The reversal of 2147401876483 is 3846781047412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2147401876483 - 21 = 2147401876481 is a prime.
It is a super-2 number, since 2×21474018764832 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2147401876481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6587122158 + ... + 6587122483.
It is an arithmetic number, because the mean of its divisors is an integer number (540144030322).
Almost surely, 22147401876483 is an apocalyptic number.
2147401876483 is a deficient number, since it is larger than the sum of its proper divisors (13174244805).
2147401876483 is a wasteful number, since it uses less digits than its factorization.
2147401876483 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13174244804.
The product of its (nonzero) digits is 7225344, while the sum is 55.
The spelling of 2147401876483 in words is "two trillion, one hundred forty-seven billion, four hundred one million, eight hundred seventy-six thousand, four hundred eighty-three".
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