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21475873483 = 33164881793
BaseRepresentation
bin10100000000000011…
…111101001011001011
32001102200122102001121
4110000003331023023
5322440310422413
613511010300111
71360122625021
oct240003751313
961380572047
1021475873483
119120630679
1241b4287637
1320433a045c
14107a308711
1585a5ebb8d
hex5000fd2cb

21475873483 has 4 divisors (see below), whose sum is σ = 21540755608. Its totient is φ = 21410991360.

The previous prime is 21475873477. The next prime is 21475873541. The reversal of 21475873483 is 38437857412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21475873483 - 225 = 21442319051 is a prime.

It is a super-2 number, since 2×214758734832 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21475873483.

It is not an unprimeable number, because it can be changed into a prime (21475873453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32440566 + ... + 32441227.

It is an arithmetic number, because the mean of its divisors is an integer number (5385188902).

Almost surely, 221475873483 is an apocalyptic number.

21475873483 is a deficient number, since it is larger than the sum of its proper divisors (64882125).

21475873483 is an equidigital number, since it uses as much as digits as its factorization.

21475873483 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64882124.

The product of its digits is 4515840, while the sum is 52.

The spelling of 21475873483 in words is "twenty-one billion, four hundred seventy-five million, eight hundred seventy-three thousand, four hundred eighty-three".

Divisors: 1 331 64881793 21475873483